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A taxicab moving at 28 m/s applies its brakes and stops. If its brakes can decelerate it at 3.6 m/s2, how much time does it take the taxicab to stop?
vo = 28 m/s
a = -3.6 m/s2
v = 0 m/s
= ?
, but:
= 0 m/s - 28 m/s = -28 m/s
The taxicab would take 7.8 seconds to stop.
Note:
This is a 2-step solution since you have to find as an intermediate step, but each step is pretty simple.
BHS -> Staff -> Mr. Stanbrough -> Physics -> Mechanics -> Kinematics -> Using v = vo + at -> this page