An Alternate Solution for Example 3


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A taxicab moving at 28 m/s applies its brakes and stops. If its brakes can decelerate it at 3.6 m/s2, how much time does it take the taxicab to stop?

Solution:

example 3 diagram

vo = 28 m/s

a = -3.6 m/s2

v = 0 m/s

delta t = ?

a = delta_v/delta_t, but:

delta_v = v - vo

delta v = 0 m/s - 28 m/s = -28 m/s

delta_t = 7.8 s

The taxicab would take 7.8 seconds to stop.

Note:

This is a 2-step solution since you have to find delta v as an intermediate step, but each step is pretty simple.


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last update August 2, 2001 by JL Stanbrough